What is the solution for y^'=(5x^5e^{y/x}+x^3y^2)/(x^4y) ?

The solution for y^'=(5x^5e^{y/x}+x^3y^2)/(x^4y) is y=-\W((5ln(x)+c_{1})/e)x-x

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y^'=(5x^5e^{y/x}+x^3y^2)/(x^4y)

y^{^{'}} = \frac{5 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{5 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

Solve using substitution:

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

\int (\frac{x + 5}{x ^{2} + 5 x + 6}) d x

\frac{1}{s + \frac{1}{2}}

f (x) = \frac{4}{x ^{7}}

4 t - e^{- 3 t}

f (x) = 20 (x - 1) e^{- 0.5 x}, at x = 4

What is the solution for y^'=(5x^5e^{y/x}+x^3y^2)/(x^4y) ?
The solution for y^'=(5x^5e^{y/x}+x^3y^2)/(x^4y) is y=-\W((5ln(x)+c_{1})/e)x-x