What is the solution for y^{''}-7y^'=2t ?

The solution for y^{''}-7y^'=2t is y=c_{1}e^{7t}+c_{2}-(t^2)/7-(2t)/(49)

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y^{''}-7y^'=2t

y^{^{''}} - 7 y^{^{'}} = 2 t

y = c_{1} e^{7 t} + c_{2} - \frac{t ^{2}}{7} - \frac{2 t}{49}

Solution steps

y^{''} (t) - 7 y^{'} (t) = 2 t

Solve linear ODE:

y = c_{1} e^{7 t} + c_{2} - \frac{t ^{2}}{7} - \frac{2 t}{49}

y = c_{1} e^{7 t} + c_{2} - \frac{t ^{2}}{7} - \frac{2 t}{49}

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What is the solution for y^{''}-7y^'=2t ?
The solution for y^{''}-7y^'=2t is y=c_{1}e^{7t}+c_{2}-(t^2)/7-(2t)/(49)