What is the integral from 0 to 1 of (85)/(x^5) ?

The integral from 0 to 1 of (85)/(x^5) is diverges

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integral from 0 to 1 of (85)/(x^5)

\int_{0}^{1} \frac{85}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{85}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 85 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 85 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\frac{d}{d x} (\frac{x}{9 + x})

f (x) = x^{2} + 10

\int sin^{2} (\frac{x}{4}) d x

y^{^{'}} + x y = x y^{- 1}

\frac{d}{d x} (x ey (x)^{2} + y ln (x))

What is the integral from 0 to 1 of (85)/(x^5) ?
The integral from 0 to 1 of (85)/(x^5) is diverges