What is the (tan(x/2))^' ?

The (tan(x/2))^' is sec^2(x/2) 1/2

What is the first (tan(x/2))^' ?

The first (tan(x/2))^' is sec^2(x/2) 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(tan (\frac{x}{2}))^{^{'}}

sec^{2} (\frac{x}{2}) \frac{1}{2}

Solution steps

(tan (\frac{x}{2}))^{'}

Apply the chain rule:

sec^{2} (\frac{x}{2}) (\frac{x}{2})^{'}

= sec^{2} (\frac{x}{2}) (\frac{x}{2})^{'}

(\frac{x}{2})^{'} = \frac{1}{2}

= sec^{2} (\frac{x}{2}) \frac{1}{2}

t \to 0 lim (t (ln (t)))

\int_{- 1}^{0} x 1 - x^{2} d x

\frac{d}{d x} (a (sin (x) - x cos (x)))

\int x ln (x - 2) d x

\int \frac{e ^{x}}{1 - e ^{x}} d x