What is the limit as x approaches 0 of (x^2+1)/(x-1) ?

The limit as x approaches 0 of (x^2+1)/(x-1) is -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (x^2+1)/(x-1)

x \to 0 lim (\frac{x ^{2} + 1}{x - 1})

- 1

Solution steps

x \to 0 lim (\frac{x ^{2} + 1}{x - 1})

Plug in the value

x = 0

= \frac{0 ^{2} + 1}{0 - 1}

Simplify

\frac{0 ^{2} + 1}{0 - 1} : - 1

= - 1

(x + y + 1) d x - (y - x + 3) d y = 0

x \to - 1 lim (7 ∣ x + 1 ∣ - 4)

\int e^{2 x} d x

\int \frac{x ( 6 x ^{2} + 6 )}{x ^{2} + 1} d x

\frac{d}{d x} (- 2 sin (x) - sin (2 x))

What is the limit as x approaches 0 of (x^2+1)/(x-1) ?
The limit as x approaches 0 of (x^2+1)/(x-1) is -1