What is the solution for d/(dt)x+7x=5cos(2t) ?

The solution for d/(dt)x+7x=5cos(2t) is x=(5(2sin(2t)+7cos(2t)))/(53)+(c_{1})/(e^{7t)}

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d/(dt)x+7x=5cos(2t)

\frac{d}{d t} x + 7 x = 5 cos (2 t)

x = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

Solution steps

\frac{d x}{d t} + 7 x = 5 cos (2 t)

Solve linear ODE:

x = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

x = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

\int_{1}^{3} x 3^{x^{2}} d x

g (x) = 27 x^{2} - x^{3}

y = 4 - 9 x^{2}, (- 3, - 77)

\int \frac{3 x}{x ^{4} + 1} d x

\frac{1}{3 + 2 x}

What is the solution for d/(dt)x+7x=5cos(2t) ?
The solution for d/(dt)x+7x=5cos(2t) is x=(5(2sin(2t)+7cos(2t)))/(53)+(c_{1})/(e^{7t)}