What is the (sqrt(2x+4))^' ?

The (sqrt(2x+4))^' is 1/(sqrt(2x+4))

What is the first (sqrt(2x+4))^' ?

The first (sqrt(2x+4))^' is 1/(sqrt(2x+4))

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(2 x + 4)^{^{'}}

\frac{1}{2 x + 4}

Solution steps

(2 x + 4)^{'}

Apply the chain rule:

\frac{1}{2 2 x + 4} (2 x + 4)^{'}

= \frac{1}{2 2 x + 4} (2 x + 4)^{'}

(2 x + 4)^{'} = 2

= \frac{1}{2 2 x + 4} \cdot 2

Simplify

\frac{1}{2 2 x + 4} \cdot 2 : \frac{1}{2 x + 4}

= \frac{1}{2 x + 4}

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