What is the derivative of cos(xdx) ?

The derivative of cos(xdx) is d(-xsin(x)+cos(x))

What is the first derivative of cos(xdx) ?

The first derivative of cos(xdx) is d(-xsin(x)+cos(x))

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\frac{d}{d x} (cos (x) d x)

d (- x sin (x) + cos (x))

Solution steps

\frac{d}{d x} (cos (x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (cos (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = cos (x), g = x

= d (\frac{d}{d x} (cos (x)) x + \frac{d x}{d x} cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d x}{d x} = 1

= d ((- sin (x)) x + 1 \cdot cos (x))

Simplify

= d (- x sin (x) + cos (x))

\int - 4 sin (2 t - \frac{π}{2}) d t

\frac{d}{d x} (\frac{x tan ( x )}{x ^{2} + 1})

f (x) = \frac{1}{2 x + 3}

y^{^{'}} + \frac{2}{x} y = \frac{1}{x ^{2}}

\frac{d}{d x} (\frac{3 x ^{2} + 2 x - 1}{( 1 + 3 x ^{2} ) ^{2}})

What is the derivative of cos(xdx) ?
The derivative of cos(xdx) is d(-xsin(x)+cos(x))
What is the first derivative of cos(xdx) ?
The first derivative of cos(xdx) is d(-xsin(x)+cos(x))