What is the limit as x approaches-1 of (x+1)/(x^2-1) ?

The limit as x approaches-1 of (x+1)/(x^2-1) is -1/2

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limit as x approaches-1 of (x+1)/(x^2-1)

x \to - 1 lim (\frac{x + 1}{x ^{2} - 1})

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

x \to - 1 lim (\frac{x + 1}{x ^{2} - 1})

Simplify

\frac{x + 1}{x ^{2} - 1} : \frac{1}{x - 1}

= x \to - 1 lim (\frac{1}{x - 1})

Plug in the value

x = - 1

= \frac{1}{- 1 - 1}

Simplify

= - \frac{1}{2}

\int 2 4 - x^{2} d x

x \to π lim (\frac{( e ^{s i n (x)} - 1 )}{x - π})

x \to - \infty lim (7 x e^{x})

\frac{d y}{d x}, arctan (x y) = arcsin (2 x + 2 y), (0, 0)

2 t y^{^{'}} - 4 y = 4 t^{4} e^{t^{2}}

What is the limit as x approaches-1 of (x+1)/(x^2-1) ?
The limit as x approaches-1 of (x+1)/(x^2-1) is -1/2