What is the tangent of y=2x+x^2,(-2,0) ?

The tangent of y=2x+x^2,(-2,0) is y=-2x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=2x+x^2,(-2,0)

tangent of

y = 2 x + x^{2}, (- 2, 0)

y = - 2 x - 4

Solution steps

Find the slope of

y = 2 x + x^{2} : \frac{d y}{d x} = 2 + 2 x

Compute the slope of

y = 2 x + x^{2}

(- 2, 0) : m = - 2

Find the line with slope m=

- 2

and passing through

(- 2, 0) : y = - 2 x - 4

y = - 2 x - 4

\int x \cdot x d x

y = (x^{2} - 7 x)^{2}

\frac{x}{x ^{2} + 100}

\int_{0}^{2} \frac{1}{x} d x

f^{^{'}} (x) = 3 x^{2}

What is the tangent of y=2x+x^2,(-2,0) ?
The tangent of y=2x+x^2,(-2,0) is y=-2x-4