What is the solution for y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=3 ?

The solution for y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=3 is y=3e^{5t}t

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y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=3

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 0, y^{^{'}} (0) = 3

y = 3 e^{5 t} t

Solution steps

y^{''} (t) - 10 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = 3 e^{5 t} t

y = 3 e^{5 t} t

\int x e^{- 2 x} d x

\int \frac{x ^{2}}{x - 7} d x

\frac{d}{d x} (\frac{1}{x ^{4}} - \frac{3}{x ^{2}})

\frac{d}{d x} (\frac{1 - x}{1 + x})

x (3 x - 2)

What is the solution for y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=3 ?
The solution for y^{''}-10y^'+25y=0,y(0)=0,y^'(0)=3 is y=3e^{5t}t