What is the derivative of (4x^2+1^2) ?

The derivative of (4x^2+1^2) is 16x(4x^2+1)

What is the first derivative of (4x^2+1^2) ?

The first derivative of (4x^2+1^2) is 16x(4x^2+1)

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\frac{d}{d x} ((4 x^{2} + 1)^{2})

16 x (4 x^{2} + 1)

Solution steps

\frac{d}{d x} ((4 x^{2} + 1)^{2})

Apply the chain rule:

2 (4 x^{2} + 1) \frac{d}{d x} (4 x^{2} + 1)

= 2 (4 x^{2} + 1) \frac{d}{d x} (4 x^{2} + 1)

\frac{d}{d x} (4 x^{2} + 1) = 8 x

= 2 (4 x^{2} + 1) \cdot 8 x

Simplify

= 16 x (4 x^{2} + 1)

\int \frac{1}{x ^{4} ( x ^{2} + 3 ) ^{\frac{1}{2}}} d x

x \to 0 + lim (e^{\frac{5}{x}})

\frac{d}{d x} ((x^{8} - 2)^{3})

\frac{\partial}{\partial x} (4 y^{3} + 2 x^{2} y + 1)

\frac{d y}{d x} x + 7 y = e^{x^{7}}

What is the derivative of (4x^2+1^2) ?
The derivative of (4x^2+1^2) is 16x(4x^2+1)
What is the first derivative of (4x^2+1^2) ?
The first derivative of (4x^2+1^2) is 16x(4x^2+1)