What is the derivative of 3/((2x-1^3)) ?

The derivative of 3/((2x-1^3)) is -(18)/((2x-1)^4)

What is the first derivative of 3/((2x-1^3)) ?

The first derivative of 3/((2x-1^3)) is -(18)/((2x-1)^4)

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\frac{d}{d x} (\frac{3}{( 2 x - 1 ) ^{3}})

- \frac{18}{( 2 x - 1 ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{3}{( 2 x - 1 ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( 2 x - 1 ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((2 x - 1)^{- 3})

Apply the chain rule:

- \frac{3}{( 2 x - 1 ) ^{4}} \frac{d}{d x} (2 x - 1)

= - \frac{3}{( 2 x - 1 ) ^{4}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 3 (- \frac{3}{( 2 x - 1 ) ^{4}} \cdot 2)

Simplify

3 (- \frac{3}{( 2 x - 1 ) ^{4}} \cdot 2) : - \frac{18}{( 2 x - 1 ) ^{4}}

= - \frac{18}{( 2 x - 1 ) ^{4}}

\frac{d}{d x} (\frac{1 + x}{1 - x})

(t^{3} - 3 t + 2) e^{- 2 t}

\int_{0}^{5} \frac{1}{1 + x ^{2}} d x

(y^{2} + x y^{2}) (\frac{d y}{d x}) = 1

What is the derivative of 3/((2x-1^3)) ?
The derivative of 3/((2x-1^3)) is -(18)/((2x-1)^4)
What is the first derivative of 3/((2x-1^3)) ?
The first derivative of 3/((2x-1^3)) is -(18)/((2x-1)^4)