What is the derivative of-x^2+6x-4 ?

The derivative of-x^2+6x-4 is -2x+6

What is the first derivative of-x^2+6x-4 ?

The first derivative of-x^2+6x-4 is -2x+6

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\frac{d}{d x} (- x^{2} + 6 x - 4)

- 2 x + 6

Solution steps

\frac{d}{d x} (- x^{2} + 6 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (4) = 0

= - 2 x + 6 - 0

Simplify

= - 2 x + 6

\int n x^{n} d x

\int \frac{1}{x ^{2} 3 - x ^{2}} d x

x \to \infty lim (- 2 x)

\frac{2 x ^{4} + 1}{y} \frac{d y}{d x} + \frac{1}{6} y^{3} x^{3} = 0

\frac{1}{2 x}

What is the derivative of-x^2+6x-4 ?
The derivative of-x^2+6x-4 is -2x+6
What is the first derivative of-x^2+6x-4 ?
The first derivative of-x^2+6x-4 is -2x+6