What is the tangent of y=(4x+5)/(x-1),(2,13) ?

The tangent of y=(4x+5)/(x-1),(2,13) is y=-9x+31

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tangent of y=(4x+5)/(x-1),(2,13)

tangent of

y = \frac{4 x + 5}{x - 1}, (2, 13)

y = - 9 x + 31

Solution steps

Find the slope of

y = \frac{4 x + 5}{x - 1} : \frac{d y}{d x} = - \frac{9}{( x - 1 ) ^{2}}

Compute the slope of

y = \frac{4 x + 5}{x - 1}

(2, 13) : m = - 9

Find the line with slope m=

- 9

and passing through

(2, 13) : y = - 9 x + 31

y = - 9 x + 31

\frac{d}{d x} (a sec (x))

\int \frac{ln ( x ^{6} )}{x} d x

\int e^{- s t} cos (b t) d t

\int \frac{1}{x + 3} d x

\int sin (x) y d x

What is the tangent of y=(4x+5)/(x-1),(2,13) ?
The tangent of y=(4x+5)/(x-1),(2,13) is y=-9x+31