What is the limit as x approaches-2 of (x-2)/(x^3+8) ?

The limit as x approaches-2 of (x-2)/(x^3+8) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-2 of (x-2)/(x^3+8)

x \to - 2 lim (\frac{x - 2}{x ^{3} + 8})

diverges

Solution steps

x \to - 2 lim (\frac{x - 2}{x ^{3} + 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 2 + lim (\frac{x - 2}{x ^{3} + 8}) = - \infty

x \to - 2 - lim (\frac{x - 2}{x ^{3} + 8}) = \infty

= diverges

\frac{\partial}{\partial θ} (r (θ) \cdot sin (θ))

\frac{\partial}{\partial x} (x z e^{x z})

cos (sin (tan (9 x)))

x^{3} + y^{3} - 4 x y = 0, (2, 2)

G (t) = \frac{1 - 4 t}{3 + t}

What is the limit as x approaches-2 of (x-2)/(x^3+8) ?
The limit as x approaches-2 of (x-2)/(x^3+8) is diverges