What is the sum from n=1 to infinity of n(n+1) ?

The sum from n=1 to infinity of n(n+1) is diverges

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sum from n=1 to infinity of n(n+1)

n = 1 \sum \infty n (n + 1)

diverges

Solution steps

n = 1 \sum \infty n (n + 1)

Apply Series Divergence Test:

diverges

= diverges

x \to 3 lim (x^{2} - 3 x)

\int (a^{\frac{2}{3}} - x^{\frac{2}{3}})^{2} d x

\int cos^{2} (6 x) sin^{3} (6 x) d x

\int \frac{10}{5 - x} d x

\frac{1}{( 1 - x ) ^{2}}

What is the sum from n=1 to infinity of n(n+1) ?
The sum from n=1 to infinity of n(n+1) is diverges