What is (\partial)/(\partial x)(e^{-x}sec(y)) ?

The answer to (\partial)/(\partial x)(e^{-x}sec(y)) is -e^{-x}sec(y)

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(\partial)/(\partial x)(e^{-x}sec(y))

\frac{\partial}{\partial x} (e^{- x} sec (y))

- e^{- x} sec (y)

Solution steps

\frac{\partial}{\partial x} (e^{- x} sec (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sec (y) \frac{\partial}{\partial x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{\partial}{\partial x} (- x)

= e^{- x} \frac{\partial}{\partial x} (- x)

\frac{\partial}{\partial x} (- x) = - 1

= sec (y) e^{- x} (- 1)

Simplify

= - e^{- x} sec (y)

\int \frac{2}{8 + 2 x} d x

\frac{d}{d x} (\frac{1}{2 x + 6})

\int t 2^{t + 2} d t

n \to \infty lim (\frac{1 n}{3})

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What is (\partial)/(\partial x)(e^{-x}sec(y)) ?
The answer to (\partial)/(\partial x)(e^{-x}sec(y)) is -e^{-x}sec(y)