What is maclaurin 3/(1+x-2x^2) ?

The answer to maclaurin 3/(1+x-2x^2) is 3-3x+9x^2-15x^3+33x^4+\ldots

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maclaurin 3/(1+x-2x^2)

maclaurin

\frac{3}{1 + x - 2 x ^{2}}

3 - 3 x + 9 x^{2} - 15 x^{3} + 33 x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

= 3 + \frac{\frac{d}{d x} ( \frac{3}{1 + x - 2 x ^{2}} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{3}{1 + x - 2 x ^{2}} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{3}{1 + x - 2 x ^{2}} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 3 + \frac{- 3}{1 !} x + \frac{18}{2 !} x^{2} + \frac{- 90}{3 !} x^{3} + \frac{792}{4 !} x^{4} + \dots

Refine

= 3 - 3 x + 9 x^{2} - 15 x^{3} + 33 x^{4} + \dots

\int cos (\frac{π y}{2}) d y

\frac{d}{d x} (a sin (3 x) + b cos (3 x))

e^{- 4 x}

\int 5 - 4 x - x^{2} d x

\int_{0}^{a} a^{2} - x^{2} d x

What is maclaurin 3/(1+x-2x^2) ?
The answer to maclaurin 3/(1+x-2x^2) is 3-3x+9x^2-15x^3+33x^4+\ldots