What is the derivative of 3x^2-7x^3+x^4-5-3x ?

The derivative of 3x^2-7x^3+x^4-5-3x is 4x^3-21x^2+6x-3

What is the first derivative of 3x^2-7x^3+x^4-5-3x ?

The first derivative of 3x^2-7x^3+x^4-5-3x is 4x^3-21x^2+6x-3

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derivative of

3 x^{2} - 7 x^{3} + x^{4} - 5 - 3 x

4 x^{3} - 21 x^{2} + 6 x - 3

Solution steps

\frac{d}{d x} (3 x^{2} - 7 x^{3} + x^{4} - 5 - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (7 x^{3}) + \frac{d}{d x} (x^{4}) - \frac{d}{d x} (5) - \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (7 x^{3}) = 21 x^{2}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (5) = 0

\frac{d}{d x} (3 x) = 3

= 6 x - 21 x^{2} + 4 x^{3} - 0 - 3

Simplify

= 4 x^{3} - 21 x^{2} + 6 x - 3

(1.2) (0.8)

y^{^{'}} = \frac{( t ^{2} + 3 y ^{2} )}{2 t y}

n = 0 \sum \infty (- \frac{7}{10})^{n}

2 y = 4 x - x^{2}, 2 y = x - 4

f (x) = x^{2} + 4 x - 3

What is the derivative of 3x^2-7x^3+x^4-5-3x ?
The derivative of 3x^2-7x^3+x^4-5-3x is 4x^3-21x^2+6x-3
What is the first derivative of 3x^2-7x^3+x^4-5-3x ?
The first derivative of 3x^2-7x^3+x^4-5-3x is 4x^3-21x^2+6x-3