What is the solution for (3xy^2+13y)+(3x^2y+13x)y^'=0 ?

The solution for (3xy^2+13y)+(3x^2y+13x)y^'=0 is y=(c_{1})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3xy^2+13y)+(3x^2y+13x)y^'=0

(3 x y^{2} + 13 y) + (3 x^{2} y + 13 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(3 x y^{2} + 13 y) + (3 x^{2} y + 13 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\int x^{2} - 1 d x

\frac{u}{u ^{2} + 7}

\int t^{- 1} d t

\int (4 x - \frac{4}{x}) d x

x^{3} (x - 8)^{2}

What is the solution for (3xy^2+13y)+(3x^2y+13x)y^'=0 ?
The solution for (3xy^2+13y)+(3x^2y+13x)y^'=0 is y=(c_{1})/x