What is the derivative of 2^x-x^2 ?

The derivative of 2^x-x^2 is 2^xln(2)-2x

What is the first derivative of 2^x-x^2 ?

The first derivative of 2^x-x^2 is 2^xln(2)-2x

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\frac{d}{d x} (2^{x} - x^{2})

2^{x} ln (2) - 2 x

Solution steps

\frac{d}{d x} (2^{x} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (x^{2}) = 2 x

= 2^{x} ln (2) - 2 x

\int_{0}^{1} x^{2} - x d x

y = \frac{x + 1}{x - 2}

\frac{d}{d x} (9 + x + y^{2})

\int x^{13} sin (x^{14}) d x

\frac{d}{d x} (x^{3} - x^{2} - x)

What is the derivative of 2^x-x^2 ?
The derivative of 2^x-x^2 is 2^xln(2)-2x
What is the first derivative of 2^x-x^2 ?
The first derivative of 2^x-x^2 is 2^xln(2)-2x