What is the integral from-infinity to 0 of 1/(6-2x) ?

The integral from-infinity to 0 of 1/(6-2x) is diverges

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integral from-infinity to 0 of 1/(6-2x)

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x

Compute the indefinite integral:

\int \frac{1}{6 - 2 x} d x = - \frac{1}{2} ln ∣ 6 - 2 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x =

diverges

= diverges

\frac{d}{d x} (\frac{3}{1 - x ^{2}})

\frac{\partial}{\partial x} (\frac{M}{2 p x})

x \to 3 lim (3 x^{4} + 2 x^{2} - 5)

f (x) = (- 3 x^{2} + 2 x + 4)^{12}

\frac{d}{d x} (1 - 169 x^{2} arccos (13 x))

What is the integral from-infinity to 0 of 1/(6-2x) ?
The integral from-infinity to 0 of 1/(6-2x) is diverges