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Popular >

derivative of 3/(x^2)-8\sqrt[4]{x}

Solution

derivative of

Solution

\frac{- 6 x ^{\frac{3}{4}} - 2 x ^{3}}{x ^{\frac{15}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

= - \frac{6}{x ^{3}} - \frac{2}{x ^{\frac{3}{4}}}

Simplify

- \frac{6}{x ^{3}} - \frac{2}{x ^{\frac{3}{4}}} : \frac{- 6 x ^{\frac{3}{4}} - 2 x ^{3}}{x ^{\frac{15}{4}}}

= \frac{- 6 x ^{\frac{3}{4}} - 2 x ^{3}}{x ^{\frac{15}{4}}}

Popular Examples

derivative of (3x+2(4x-3))

\frac{d}{d x} ((3 x + 2) (4 x - 3))

derivative of (x^3-4x*e^{3x})

\frac{d}{d x} ((x^{3} - 4 x) \cdot e^{3 x})

y^{^{'''}} - 8 = 0

sum from n=0 to infinity of (2n)/(n^2)

n = 0 \sum \infty \frac{2 n}{n ^{2}}

(\partial)/(\partial y)((xy^2+x^3)^4)

\frac{\partial}{\partial y} ((x y^{2} + x^{3})^{4})

Frequently Asked Questions (FAQ)

What is the derivative of 3/(x^2)-8\sqrt[4]{x} ?
The derivative of 3/(x^2)-8\sqrt[4]{x} is (-6x^{3/4}-2x^3)/(x^{15/4)}
What is the first derivative of 3/(x^2)-8\sqrt[4]{x} ?
The first derivative of 3/(x^2)-8\sqrt[4]{x} is (-6x^{3/4}-2x^3)/(x^{15/4)}