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Popular >

y^'+4y=e^{-x}

Solution

y^{^{'}} + 4 y = e^{- x}

Solution

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

Solution steps

y^{'} (x) + 4 y = e^{- x}

Solve linear ODE:

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

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\int_{0}^{2 π} cos (x) sin (x) d x

limit as x approaches-6 of 11x+3

x \to - 6 lim (11 x + 3)

Frequently Asked Questions (FAQ)

What is the solution for y^'+4y=e^{-x} ?
The solution for y^'+4y=e^{-x} is y= 1/(3e^x)+(c_{1})/(e^{4x)}