What is the derivative of (3x^2+6^3) ?

The derivative of (3x^2+6^3) is 18x(3x^2+6)^2

What is the first derivative of (3x^2+6^3) ?

The first derivative of (3x^2+6^3) is 18x(3x^2+6)^2

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\frac{d}{d x} ((3 x^{2} + 6)^{3})

18 x (3 x^{2} + 6)^{2}

Solution steps

\frac{d}{d x} ((3 x^{2} + 6)^{3})

Apply the chain rule:

3 (3 x^{2} + 6)^{2} \frac{d}{d x} (3 x^{2} + 6)

= 3 (3 x^{2} + 6)^{2} \frac{d}{d x} (3 x^{2} + 6)

\frac{d}{d x} (3 x^{2} + 6) = 6 x

= 3 (3 x^{2} + 6)^{2} \cdot 6 x

Simplify

= 18 x (3 x^{2} + 6)^{2}

\frac{\partial}{\partial x} (e^{y x})

f (x) = ln (x + 1)

x \to \infty lim (- 3 x^{4})

\int tan^{2} (x se) c^{10} x d x

\int 2 1 - e^{- x} e^{- x} d x

What is the derivative of (3x^2+6^3) ?
The derivative of (3x^2+6^3) is 18x(3x^2+6)^2
What is the first derivative of (3x^2+6^3) ?
The first derivative of (3x^2+6^3) is 18x(3x^2+6)^2