What is the integral of-sin(x)tan(x) ?

The integral of-sin(x)tan(x) is -ln|tan(x)+sec(x)|+sin(x)+C

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integral of-sin(x)tan(x)

\int - sin (x) tan (x) d x

- ln ∣ tan (x) + sec (x) ∣ + sin (x) + C

Solution steps

\int - sin (x) tan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sin (x) tan (x) d x

Rewrite using trig identities

= - \int \frac{1 - cos ^{2} ( x )}{cos ( x )} d x

Expand

\frac{1 - cos ^{2} ( x )}{cos ( x )} : \frac{1}{cos ( x )} - cos (x)

= - \int \frac{1}{cos ( x )} - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int \frac{1}{cos ( x )} d x - \int cos (x) d x)

\int \frac{1}{cos ( x )} d x = ln ∣ tan (x) + sec (x) ∣

\int cos (x) d x = sin (x)

= - (ln ∣ tan (x) + sec (x) ∣ - sin (x))

Simplify

= - ln ∣ tan (x) + sec (x) ∣ + sin (x)

Add a constant to the solution

= - ln ∣ tan (x) + sec (x) ∣ + sin (x) + C

\frac{1}{( s + 2 ) ^{2} + 1}

\frac{8 - x e ^{x}}{x + e ^{x}}

\int \frac{x + x ^{3}}{x} - e^{x} d x

f (x) = \frac{e ^{x} - e ^{- x}}{2}

\int x^{3} e^{3 x} d x

What is the integral of-sin(x)tan(x) ?
The integral of-sin(x)tan(x) is -ln|tan(x)+sec(x)|+sin(x)+C