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Popular >

y^'=e^{t-y}

Solution

y^{^{'}} = e^{t - y}

Solution

y = ln (e^{t} + c_{1})

Solution steps

y^{'} (t) = e^{t - y}

Solve separable ODE:

y = ln (e^{t} + c_{1})

y = ln (e^{t} + c_{1})

Popular Examples

integral of (3x-11)e^x

\int (3 x - 11) e^{x} d x

3y^{''}-7y^'+2y=0,y(0)=-3,y^'(0)=-8

3 y^{^{''}} - 7 y^{^{'}} + 2 y = 0, y (0) = - 3, y^{^{'}} (0) = - 8

integral of sin(x)-8cos(x)

\int sin (x) - 8 cos (x) d x

derivative of f(x)=cot(7x)derivative of

f (x) = cot (7 x)

limit as x approaches 0 of ((1/((x+4)))-(1/4))/x

x \to 0 lim \frac{( \frac{1}{( x + 4 )} ) - ( \frac{1}{4} )}{x}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{t-y} ?
The solution for y^'=e^{t-y} is y=ln(e^t+c_{1})