What is the solution for (1+x)y^'+y=cos(x) ?

The solution for (1+x)y^'+y=cos(x) is y=(sin(x))/(1+x)+(c_{1})/(1+x)

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(1+x)y^'+y=cos(x)

(1 + x) y^{^{'}} + y = cos (x)

y = \frac{sin ( x )}{1 + x} + \frac{c _{1}}{1 + x}

Solution steps

(1 + x) y^{'} (x) + y = cos (x)

Solve linear ODE:

y = \frac{sin ( x )}{1 + x} + \frac{c _{1}}{1 + x}

y = \frac{sin ( x )}{1 + x} + \frac{c _{1}}{1 + x}

\frac{\partial}{\partial x} (e^{x} sin (3 y))

n = 1 \sum \infty \frac{2}{n !}

\int 5^{3} d x

xg (x)

\frac{\partial}{\partial x} (x e^{x y} + y)

What is the solution for (1+x)y^'+y=cos(x) ?
The solution for (1+x)y^'+y=cos(x) is y=(sin(x))/(1+x)+(c_{1})/(1+x)