What is the solution for (dy)/(dx)=(xe^{3x+y^3})/(y^2) ?

The solution for (dy)/(dx)=(xe^{3x+y^3})/(y^2) is y=-\sqrt[3]{ln(-e^{3x}x+1/3 e^{3x}-c_{1})}

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(dy)/(dx)=(xe^{3x+y^3})/(y^2)

\frac{d y}{d x} = \frac{x e ^{3 x + y^{3}}}{y ^{2}}

Solution steps

\frac{d y}{d x} = \frac{x e ^{3 x + y^{3}}}{y ^{2}}

Solve separable ODE:

\frac{d}{d x} ((3 x^{3} - 4) (- 4 x - 3))

4 x^{2} y^{^{'}} = y^{^{'}} + 9 x e^{- y}

\int 1 x d x

y = 19 sin (x) cos (x)

tan (ln (a x + b))

What is the solution for (dy)/(dx)=(xe^{3x+y^3})/(y^2) ?
The solution for (dy)/(dx)=(xe^{3x+y^3})/(y^2) is y=-\sqrt[3]{ln(-e^{3x}x+1/3 e^{3x}-c_{1})}