What is the derivative of 1/((1+x^3)) ?

The derivative of 1/((1+x^3)) is -3/((1+x)^4)

What is the first derivative of 1/((1+x^3)) ?

The first derivative of 1/((1+x^3)) is -3/((1+x)^4)

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\frac{d}{d x} (\frac{1}{( 1 + x ) ^{3}})

- \frac{3}{( 1 + x ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{( 1 + x ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((1 + x)^{- 3})

Apply the chain rule:

- \frac{3}{( 1 + x ) ^{4}} \frac{d}{d x} (1 + x)

= - \frac{3}{( 1 + x ) ^{4}} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= - \frac{3}{( 1 + x ) ^{4}} \cdot 1

Simplify

= - \frac{3}{( 1 + x ) ^{4}}

4 y^{^{''}} + 16 y^{^{'}} + 19 y = 0

\frac{d}{d x} (arctan (\frac{d}{x}))

\int (x - 1) e^{x} d x

y^{^{''}} + 2 y^{^{'}} = (8 t - 7) sin (3 t)

\int e^{2 t} d t

What is the derivative of 1/((1+x^3)) ?
The derivative of 1/((1+x^3)) is -3/((1+x)^4)
What is the first derivative of 1/((1+x^3)) ?
The first derivative of 1/((1+x^3)) is -3/((1+x)^4)