What is the solution for 9x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=2 ?

The solution for 9x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=2 is y=sqrt((9\sqrt{x^2+1)-1)/2}

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9x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=2

9 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 2

y = \frac{9 x ^{2} + 1 - 1}{2}

Solution steps

9 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{9 x ^{2} + 1 - 1}{2}

y = \frac{9 x ^{2} + 1 - 1}{2}

f (x) = 5 - 2 x^{2}, at x = - 2

\int \frac{2 x + 1}{( - 4 x ^{2} + 4 x + 3 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (sin (3 x + 2))

\frac{4}{( s + 10 ) ( s ^{2} + 16 ) ^{2}}

y = \frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

What is the solution for 9x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=2 ?
The solution for 9x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=2 is y=sqrt((9\sqrt{x^2+1)-1)/2}