What is the derivative of-7e^{(x+2)}+e^5 ?

The derivative of-7e^{(x+2)}+e^5 is -7e^{x+2}

What is the first derivative of-7e^{(x+2)}+e^5 ?

The first derivative of-7e^{(x+2)}+e^5 is -7e^{x+2}

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derivative of

- 7 e^{(x + 2)} + e^{5}

- 7 e^{x + 2}

Solution steps

\frac{d}{d x} (- 7 e^{x + 2} + e^{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (7 e^{x + 2}) + \frac{d}{d x} (e^{5})

\frac{d}{d x} (7 e^{x + 2}) = 7 e^{x + 2}

\frac{d}{d x} (e^{5}) = 0

= - 7 e^{x + 2} + 0

Simplify

= - 7 e^{x + 2}

(6, - 7), (8, 5)

\frac{\partial}{\partial y} (4 y^{2} - 20)

f (x) = 8 ln (x) - x^{2}

\frac{d y}{d x} = 10 - 2 y

\frac{d}{d x} (sin (x^{8}))

What is the derivative of-7e^{(x+2)}+e^5 ?
The derivative of-7e^{(x+2)}+e^5 is -7e^{x+2}
What is the first derivative of-7e^{(x+2)}+e^5 ?
The first derivative of-7e^{(x+2)}+e^5 is -7e^{x+2}