What is the solution for y^'+tan(3x)y=0,y(0)=3 ?

The solution for y^'+tan(3x)y=0,y(0)=3 is y=cos^{1/3}(3x)*3

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y^'+tan(3x)y=0,y(0)=3

y^{^{'}} + tan (3 x) y = 0, y (0) = 3

y = cos^{\frac{1}{3}} (3 x) \cdot 3

Solution steps

y^{'} (x) + tan (3 x) y = 0

Solve separable ODE:

y = cos^{\frac{1}{3}} (3 x) \cdot 3

y = cos^{\frac{1}{3}} (3 x) \cdot 3

\frac{π}{3}

f (x) = x^{3}

\frac{\partial}{\partial x} (6 e^{x - y})

\frac{d}{d x} (\frac{1}{3} x)

\int x 1 + 4 x^{2} d x

What is the solution for y^'+tan(3x)y=0,y(0)=3 ?
The solution for y^'+tan(3x)y=0,y(0)=3 is y=cos^{1/3}(3x)*3