What is the derivative of f(x)=2xe^xcsc(x) ?

The derivative of f(x)=2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

What is the first derivative of f(x)=2xe^xcsc(x) ?

The first derivative of f(x)=2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 2 x e^{x} csc (x)

2 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

Solution steps

\frac{d}{d x} (2 x e^{x} csc (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x e^{x} csc (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x} csc (x)

= 2 (\frac{d x}{d x} e^{x} csc (x) + \frac{d}{d x} (e^{x} csc (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x} csc (x)) = e^{x} csc (x) - e^{x} cot (x) csc (x)

= 2 (1 \cdot e^{x} csc (x) + (e^{x} csc (x) - e^{x} cot (x) csc (x)) x)

Simplify

= 2 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

\frac{d}{d x} (sec^{2} (\frac{x}{2}))

\frac{d}{d x} (\frac{2 - x ^{2}}{3 x ^{2} + 1})

x \to - 1 + lim (\frac{x ^{2} + x}{x + 1})

\frac{d}{d x} (x^{2} \cdot x^{7})

\frac{\partial}{\partial y} (x^{4} y^{2} - x^{3} y)

What is the derivative of f(x)=2xe^xcsc(x) ?
The derivative of f(x)=2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))
What is the first derivative of f(x)=2xe^xcsc(x) ?
The first derivative of f(x)=2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))