What is the derivative of 2x^3+1 ?

The derivative of 2x^3+1 is 6x^2

What is the first derivative of 2x^3+1 ?

The first derivative of 2x^3+1 is 6x^2

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\frac{d}{d x} (2 x^{3} + 1)

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (1) = 0

= 6 x^{2} + 0

Simplify

= 6 x^{2}

f (x) = \frac{e ^{x}}{4 - 4 x}

\frac{\partial}{\partial y} (sin^{2} (x + y))

f (x) = 6 - x^{2}, g (x) = x

1 - 3 x

\int sin^{2} (r) d r