What is the derivative of 5xtan(x) ?

The derivative of 5xtan(x) is 5(tan(x)+xsec^2(x))

What is the first derivative of 5xtan(x) ?

The first derivative of 5xtan(x) is 5(tan(x)+xsec^2(x))

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\frac{d}{d x} (5 x tan (x))

5 (tan (x) + x sec^{2} (x))

Solution steps

\frac{d}{d x} (5 x tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (x tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = tan (x)

= 5 (\frac{d x}{d x} tan (x) + \frac{d}{d x} (tan (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 5 (1 \cdot tan (x) + sec^{2} (x) x)

Simplify

= 5 (tan (x) + x sec^{2} (x))

y^{^{'}} = t + t y^{2}, y (2) = 0

\frac{d}{d x} (\frac{12}{x ^{3}})

\frac{d}{d x} (\frac{x - 9 x x}{x})

f (x) = \frac{x}{5}

\int y^{4} - 8 y^{3} + 16 y^{2} d y

What is the derivative of 5xtan(x) ?
The derivative of 5xtan(x) is 5(tan(x)+xsec^2(x))
What is the first derivative of 5xtan(x) ?
The first derivative of 5xtan(x) is 5(tan(x)+xsec^2(x))