What is the derivative of (x^2-3^5) ?

The derivative of (x^2-3^5) is 10x(x^2-3)^4

What is the first derivative of (x^2-3^5) ?

The first derivative of (x^2-3^5) is 10x(x^2-3)^4

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\frac{d}{d x} ((x^{2} - 3)^{5})

10 x (x^{2} - 3)^{4}

Solution steps

\frac{d}{d x} ((x^{2} - 3)^{5})

Apply the chain rule:

5 (x^{2} - 3)^{4} \frac{d}{d x} (x^{2} - 3)

= 5 (x^{2} - 3)^{4} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= 5 (x^{2} - 3)^{4} \cdot 2 x

Simplify

= 10 x (x^{2} - 3)^{4}

\int \frac{2 x}{- x ^{2} - 1} d x

t \to 0 lim (\frac{( 2 + t ) ^{3} - 8}{t})

x \to - 2 lim (4 x + 1)

\frac{d y}{d t} = - 5 (y - 2)

What is the derivative of (x^2-3^5) ?
The derivative of (x^2-3^5) is 10x(x^2-3)^4
What is the first derivative of (x^2-3^5) ?
The first derivative of (x^2-3^5) is 10x(x^2-3)^4