What is the derivative of (3x-1(2x+5)) ?

The derivative of (3x-1(2x+5)) is 12x+13

What is the first derivative of (3x-1(2x+5)) ?

The first derivative of (3x-1(2x+5)) is 12x+13

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\frac{d}{d x} ((3 x - 1) (2 x + 5))

12 x + 13

Solution steps

\frac{d}{d x} ((3 x - 1) (2 x + 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x - 1, g = 2 x + 5

= \frac{d}{d x} (3 x - 1) (2 x + 5) + \frac{d}{d x} (2 x + 5) (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

\frac{d}{d x} (2 x + 5) = 2

= 3 (2 x + 5) + 2 (3 x - 1)

Simplify

3 (2 x + 5) + 2 (3 x - 1) : 12 x + 13

= 12 x + 13

x^{^{''}} - 14 x^{^{'}} + 49 x = 4 t e^{7 t}

x^{3} + 4 x

\frac{\partial}{\partial y} (x^{2} - x + g (y))

\frac{d y}{d x} = (\frac{y}{( x + 2 y )})

\int ∣ 3 - x ∣ d x

What is the derivative of (3x-1(2x+5)) ?
The derivative of (3x-1(2x+5)) is 12x+13
What is the first derivative of (3x-1(2x+5)) ?
The first derivative of (3x-1(2x+5)) is 12x+13