What is the solution for ((x^2+1)dy)/(dx)+8x(y-1)=0 ?

The solution for ((x^2+1)dy)/(dx)+8x(y-1)=0 is y=(c_{1})/(x^8+4x^6+6x^4+4x^2+1)+1

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((x^2+1)dy)/(dx)+8x(y-1)=0

\frac{( x ^{2} + 1 ) d y}{d x} + 8 x (y - 1) = 0

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

Solution steps

\frac{( x ^{2} + 1 ) d y}{d x} + 8 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

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f (x) = tan (\frac{π}{3})

\frac{d}{d x} (\frac{e ^{i x} + e ^{- i x}}{2})

\frac{\partial}{\partial y} (\frac{x}{9 + y})

What is the solution for ((x^2+1)dy)/(dx)+8x(y-1)=0 ?
The solution for ((x^2+1)dy)/(dx)+8x(y-1)=0 is y=(c_{1})/(x^8+4x^6+6x^4+4x^2+1)+1