What is the first derivative of x^2+6 ?

The first derivative of x^2+6 is 2x

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derivative of x^2+6

derivative of

x^{2} + 6

2 x

Solution steps

\frac{d}{d x} (x^{2} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6) = 0

= 2 x + 0

Simplify

= 2 x

f (x) = ln (x) + 1

x^{3} - x^{2}

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