What is the tangent of 2x^2+3x-2,\at x=0 ?

The tangent of 2x^2+3x-2,\at x=0 is y=3x-2

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tangent of 2x^2+3x-2,\at x=0

tangent of

2 x^{2} + 3 x - 2, at x = 0

y = 3 x - 2

Solution steps

Find the tangent point:

(0, - 2)

Find the slope of

y = 2 x^{2} + 3 x - 2 : \frac{d y}{d x} = 4 x + 3

Compute the slope of

y = 2 x^{2} + 3 x - 2

x = 0 : m = 3

Find the line with slope m=

3

and passing through

(0, - 2) : y = 3 x - 2

y = 3 x - 2

f (x) = \frac{3}{x ^{2}} + \frac{5}{x ^{4}}

\frac{d y}{d x} = 4 x + \frac{4 x}{16 - x ^{2}}

x \to 8 lim (\frac{3 x ^{2}}{4})

\int \frac{x e ^{2 x}}{( 1 + 2 x ) ^{2}} d x

y^{^{''}} + 4 y^{^{'}} + 3 y = 65 sin (2 t)

What is the tangent of 2x^2+3x-2,\at x=0 ?
The tangent of 2x^2+3x-2,\at x=0 is y=3x-2