What is (\partial)/(\partial y)(4x^3y^3-2) ?

The answer to (\partial)/(\partial y)(4x^3y^3-2) is 12x^3y^2

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(\partial)/(\partial y)(4x^3y^3-2)

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 2)

12 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{3} y^{3}) - \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (4 x^{3} y^{3}) = 12 x^{3} y^{2}

\frac{\partial}{\partial y} (2) = 0

= 12 x^{3} y^{2} - 0

Simplify

= 12 x^{3} y^{2}

f (x) = \frac{4 + cot ( x )}{7 - tan ( x )}

5 t

\frac{6}{s ( s + 1 ) ( s + 2 ) + 6}

\int sin (3) x^{2} d x

\frac{d}{d x} (\frac{x ^{2}}{a ^{2}})

What is (\partial)/(\partial y)(4x^3y^3-2) ?
The answer to (\partial)/(\partial y)(4x^3y^3-2) is 12x^3y^2