What is (\partial)/(\partial x)(x^2-5xy) ?

The answer to (\partial)/(\partial x)(x^2-5xy) is 2x-5y

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(\partial)/(\partial x)(x^2-5xy)

\frac{\partial}{\partial x} (x^{2} - 5 x y)

2 x - 5 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 5 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (5 x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (5 x y) = 5 y

= 2 x - 5 y

f (x) = x^{1.7}

x \to - 4 lim (\frac{x ^{2} + 9}{x + 2})

\int 16 e^{u} d u

y^{^{''}} - 4 y^{^{'}} - x + 2 = 0

\frac{d}{d x} (x^{3} + 2 x^{2} - 4 x - 8)

What is (\partial)/(\partial x)(x^2-5xy) ?
The answer to (\partial)/(\partial x)(x^2-5xy) is 2x-5y