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Popular >

xy^'=4x^2-2y,y(1)=3

Solution

x y^{^{'}} = 4 x^{2} - 2 y, y (1) = 3

Solution

y = x^{2} + \frac{2}{x ^{2}}

Solution steps

x y^{'} (x) = 4 x^{2} - 2 y

Solve linear ODE:

y = x^{2} + \frac{2}{x ^{2}}

y = x^{2} + \frac{2}{x ^{2}}

Popular Examples

area y^2-27x=0,x+y=0 area

y^{2} - 27 x = 0, x + y = 0

tangent of f(x)=x^3+4x-2,\at x=1 tangent of

f (x) = x^{3} + 4 x - 2, at x = 1

derivative of (x^{n+1}/(n+1))

\frac{d}{d x} (\frac{x ^{n + 1}}{n + 1})

derivative of 50ln(2x+1)-x/2 derivative of

50 ln (2 x + 1) - \frac{x}{2}

integral from 5 to infinity of 2/(x^3)

\int_{5}^{\infty} \frac{2}{x ^{3}} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'=4x^2-2y,y(1)=3 ?
The solution for xy^'=4x^2-2y,y(1)=3 is y=x^2+2/(x^2)