What is the integral from 0 to 1 of cos(pit) ?

The integral from 0 to 1 of cos(pit) is 0

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integral from 0 to 1 of cos(pit)

\int_{0}^{1} cos (π t) d t

0

Solution steps

\int_{0}^{1} cos (π t) d t

Apply u-substitution

: \int_{0}^{π} cos (u) \frac{1}{π} d u

= \int_{0}^{π} cos (u) \frac{1}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{π} \cdot \int_{0}^{π} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{π} [sin (u)]_{0}^{π}

Compute the boundaries:

0

= \frac{1}{π} \cdot 0

Simplify

= 0

cos (x^{2} + 5) - x^{3}

\frac{d}{d x} (ln (\frac{5 + e ^{x}}{5 - e ^{x}}))

x \to \infty lim (\frac{arctan ( x )}{\frac{1}{x} - 4})

\frac{d}{d x} (- \frac{x ^{7}}{7} + \frac{x ^{5}}{5})

y = \frac{3 x - 2}{2 x + 1}

What is the integral from 0 to 1 of cos(pit) ?
The integral from 0 to 1 of cos(pit) is 0