What is the integral of (3x-2)/(5x^2-3x+2) ?

The integral of (3x-2)/(5x^2-3x+2) is

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integral of (3x-2)/(5x^2-3x+2)

\int \frac{3 x - 2}{5 x ^{2} - 3 x + 2} d x

20 (3 (\frac{1}{200} ln 100 x^{2} - 60 x + 40 + \frac{3}{100 31} arctan (\frac{10 x - 3}{31})) - \frac{1}{5 31} arctan (\frac{10 x - 3}{31})) + C

Solution steps

\int \frac{3 x - 2}{5 x ^{2} - 3 x + 2} d x

Complete the square

5 x^{2} - 3 x + 2 : 5 (x - \frac{3}{10})^{2} + \frac{31}{20}

= \int \frac{3 x - 2}{5 ( x - \frac{3}{10} ) ^{2} + \frac{31}{20}} d x

Apply u-substitution

: \int \frac{20 ( 3 ( u + \frac{3}{10} ) - 2 )}{100 u ^{2} + 31} d u

= \int \frac{20 ( 3 ( u + \frac{3}{10} ) - 2 )}{100 u ^{2} + 31} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int \frac{3 ( u + \frac{3}{10} ) - 2}{100 u ^{2} + 31} d u

Expand

\frac{3 ( u + \frac{3}{10} ) - 2}{100 u ^{2} + 31} : \frac{3 ( u + \frac{3}{10} )}{100 u ^{2} + 31} - \frac{2}{100 u ^{2} + 31}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 20 (\int \frac{3 ( u + \frac{3}{10} )}{100 u ^{2} + 31} d u - \int \frac{2}{100 u ^{2} + 31} d u)

\int \frac{3 ( u + \frac{3}{10} )}{100 u ^{2} + 31} d u = 3 (\frac{1}{200} ln 100 u^{2} + 31 + \frac{3}{100 31} arctan (\frac{10}{31} u))

\int \frac{2}{100 u ^{2} + 31} d u = \frac{1}{5 31} arctan (\frac{10}{31} u)

= 20 (3 (\frac{1}{200} ln 100 u^{2} + 31 + \frac{3}{100 31} arctan (\frac{10}{31} u)) - \frac{1}{5 31} arctan (\frac{10}{31} u))

Substitute back

u = x - \frac{3}{10}

= 20 (3 (\frac{1}{200} ln 100 (x - \frac{3}{10})^{2} + 31 + \frac{3}{100 31} arctan (\frac{10}{31} (x - \frac{3}{10}))) - \frac{1}{5 31} arctan (\frac{10}{31} (x - \frac{3}{10})))

Simplify

20 (3 (\frac{1}{200} ln 100 (x - \frac{3}{10})^{2} + 31 + \frac{3}{100 31} arctan (\frac{10}{31} (x - \frac{3}{10}))) - \frac{1}{5 31} arctan (\frac{10}{31} (x - \frac{3}{10}))) : 20 (3 (\frac{1}{200} ln 100 x^{2} - 60 x + 40 + \frac{3}{100 31} arctan (\frac{10 x - 3}{31})) - \frac{1}{5 31} arctan (\frac{10 x - 3}{31}))

= 20 (3 (\frac{1}{200} ln 100 x^{2} - 60 x + 40 + \frac{3}{100 31} arctan (\frac{10 x - 3}{31})) - \frac{1}{5 31} arctan (\frac{10 x - 3}{31}))

Add a constant to the solution

= 20 (3 (\frac{1}{200} ln 100 x^{2} - 60 x + 40 + \frac{3}{100 31} arctan (\frac{10 x - 3}{31})) - \frac{1}{5 31} arctan (\frac{10 x - 3}{31})) + C

55 cos (0.03 x - 1.11) + 86

y^{^{''}} - 2 y^{^{'}} - 3 y = 9

5, x^{2} + 1

\int \frac{x ^{6} - x ^{4} + x ^{2}}{x ^{3}} d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 10) d x

What is the integral of (3x-2)/(5x^2-3x+2) ?
The integral of (3x-2)/(5x^2-3x+2) is