What is the tangent of y=4tan(x),\at x= pi/6 ?

The tangent of y=4tan(x),\at x= pi/6 is y= 16/3 x+4/(sqrt(3))-(8pi)/9

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tangent of y=4tan(x),\at x= pi/6

tangent of

y = 4 tan (x), at x = \frac{π}{6}

y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{4}{3})

Find the slope of

y = 4 tan (x) : \frac{d y}{d x} = 4 sec^{2} (x)

Compute the slope of

y = 4 tan (x)

x = \frac{π}{6} : m = \frac{16}{3}

Find the line with slope m=

\frac{16}{3}

and passing through

(\frac{π}{6}, \frac{4}{3}) : y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

\int_{1}^{3} (x^{2} + 1)^{3} x d x

\int_{2}^{4} \frac{1}{( x - 4 ) ( x - 1 )} d x

\int_{9}^{16} \frac{1}{2 - x} d x

\frac{\partial}{\partial y} (sin (y) + y, x)

\int_{0}^{2} t e^{t} d t

What is the tangent of y=4tan(x),\at x= pi/6 ?
The tangent of y=4tan(x),\at x= pi/6 is y= 16/3 x+4/(sqrt(3))-(8pi)/9