What is area f(x)=4x(1-x),g(x)=4x-4 ?

The answer to area f(x)=4x(1-x),g(x)=4x-4 is 16/3

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area f(x)=4x(1-x),g(x)=4x-4

area

f (x) = 4 x (1 - x), g (x) = 4 x - 4

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} ∣ 4 x (1 - x) - (4 x - 4) ∣ d x

Solve

\int_{- 1}^{1} ∣ 4 x (1 - x) - (4 x - 4) ∣ d x : \frac{16}{3}

The area is:

= \frac{16}{3}

\frac{d}{d x} (\frac{6 x ^{3} - 5 x ^{2} - 2 x}{4 x - 3 x ^{2}})

\frac{d}{d x} (5 x + \frac{100}{x})

x \to 2 lim (\frac{x + 2}{x - 2})

\frac{d}{d x} (\frac{5}{3})

\frac{d}{d x} (\frac{x ^{6}}{12} ln (x) - \frac{x ^{6}}{72})

What is area f(x)=4x(1-x),g(x)=4x-4 ?
The answer to area f(x)=4x(1-x),g(x)=4x-4 is 16/3