What is (\partial)/(\partial x)(4x^2y^2) ?

The answer to (\partial)/(\partial x)(4x^2y^2) is 8xy^2

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(\partial)/(\partial x)(4x^2y^2)

\frac{\partial}{\partial x} (4 x^{2} y^{2})

8 x y^{2}

Solution steps

\frac{\partial}{\partial x} (4 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 y^{2} \cdot 2 x^{2 - 1}

Simplify

= 8 x y^{2}

(- 2, 1), (3, - 9)

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What is (\partial)/(\partial x)(4x^2y^2) ?
The answer to (\partial)/(\partial x)(4x^2y^2) is 8xy^2